正则表达式密码验证angularjs

Question

I am new to angular js. I have created a login screen. I need to validate my password. it should contain one special character from -'$@£!%*#?&' and at least one letter and number. As of now it accepts all special characters without any limitations. I have following code

if (vm.newpassword_details.password.search("^(?=.*?[A-Za-z])(?=.*?[0-9])(?=.*?[$@£!%*#?&]).{8,}$")) {
  var msg = "Password should contain one special character from -'$@£!%*#?&' and at least one letter and number";
  alert(msg);
}

Answer 1

Note that your current regex imposes 4 types of restriction:

1. At least one ASCII letter ( (?=.*?[A-Za-z]) ),
2. At least one digit ( (?=.*?[0-9]) ),
3. At least one specific char from the set ( (?=.*?[$@£!%*#?&]) )
4. The whole string should have at least 8 chars ( .{8,} )

The . in .{8,} can match any char other than line break chars.

If you plan to restrict the . and only allow users to type the chars from your sets, create a superset from them and use it with RegExp#test :

if (!/^(?=.*?[A-Za-z])(?=.*?[0-9])(?=.*?[$@£!%*#?&])[A-Za-z0-9$@£!%*#?&]{8,}$/.test(vm.newpassword_details.password)) {  /* Error ! */  }

See the regex demo