定义函数时的语法错误

Question

I've got a syntax error when defining this function.

def questionfilehandler("filename.txt"):
    with open("filename.txt", "r") as file:
        print(file.read)
        return input()
        file.close()

I've looked up the syntax, and it all appears to be correct.
This is the error message I got
And this is the code with the error highlighted by IDLE.

Thanks to everyone who reads and tries to answer this. Your time is greatly appreciated =).

Answer 1

Assuming your indentation gets fixed, which is obvious... you cannot call a string directly as a function argument. You need a variable:

def questionfilehandler(filename):
    with open(filename, "r") as file:
        print(file.read())
        return input()
        # file.close() - not needed

Then... you can call the function with a string as its argument:

questionfilehandler("filename.txt")

Answer 2

def questionfilehandler(filename = "data.txt"): # filename has default value so it will take your input if you provide with function call.
    with open(filename) as filedata:
        # print(file.read()) # no need for this method as all work done by "open()".
        for data in filedata:
            print data

questionfilehandler() # You can pass file name if you want to else keep the default.

No need of filename.close() as "with" operator handles it automatically.