如何计算SQL中另一个事件后立即发生的事件？

Question

I have taken a data set and run the following query to filter it to the events that I want:

SELECT player_id, team_id, pbp_id, event_desc_id 
FROM GamsetPBP 
WHERE event_desc_id = '2FGM' OR event_desc_id = '3FGM' OR event_desc_id = '2FGA' OR event_desc_id ='3FGA' OR event_desc_id = 'O';

When I do this, it shows all the instances of those events. I want to count all instances where a 2FGM, 3FGM, 2FGA, or 3FGA occurs within two events of an 'O' event based on the pbp_id.

So if an 'O' has a pbp_id of 45 and there is a '2FGM' with a pbp_id of 47, I want to be able to count it. Any suggestions on how I can Count occurrences within a range like this?

Answer 1

From what I understand you could use this query:

SELECT     COUNT(DISTINCT a.pbp_id)
FROM       GamsetPBP a
INNER JOIN GamsetPBP b
        ON b.pbp_id BETWEEN a.php_id + 1 AND a.php_id + 2
       AND b.event_desc_id IN ('2FGM', '3FGM', '2FGA', '3FGA')
       -- ... any other join conditions on player_id? team_id?
WHERE      a.event_desc_id = 'O';

This counts the number of "O" events that have an event following it with an ID that is one or two greater, and which have a type that is '2FGM', '3FGM', '2FGA', or '3FGA'. There could of course be two of those following, but then the above query will only count that as one instance.

If you want to count such "doubles" separately, then remove the word DISTINCT .

From your comment it became clear that the two records (the one with "O" and the one with the other type) should belong to the same team and be counted per team, with the highest counts listed first.

In that case add the team condition in the join , select the team ID, group by it and order by the count:

SELECT     a.team_id,
           COUNT(DISTINCT a.pbp_id)
FROM       GamsetPBP a
INNER JOIN GamsetPBP b
        ON b.pbp_id BETWEEN a.php_id + 1 AND a.php_id + 2
       AND b.event_desc_id IN ('2FGM', '3FGM', '2FGA', '3FGA')
       AND b.team_id = a.team_id
WHERE      a.event_desc_id = 'O'
GROUP BY   a.team_id
ORDER BY   2 DESC;