正则表达式来检测重复字符的重复

Question

There's being a while since I last used regex... I have a string of 0s and 1s:

0010001110011000

And I have to split it by blocks of 1 (2 or more consecutive 1s):

001000 # These are the blocks what matters to me
00
000

I'm wondering how to do that.

I was trying something like this, in Python:

l = re.compile("([1])\1+").split(s)

But it is not right.

Thank you.

Answer 1

You may use

re.split(r'1{2,}', s)

See the regex demo . Here, 1{2,} matches 2 or more (due to the limiting quantifier {2,} ) 1 digits.

If the 1 s may appear at the beginning, you will need to remove empty elements, say, with filter(None, result) .

See a Python demo .