PHP数组转换为json格式

Question

I am trying to create a chart based on some php data i got in an array, if I run the following

<?php     
    $out = array_values($periodi);  
    echo json_encode($out, JSON_PRETTY_PRINT); 
?>

I get this json format

   [
    "Francia",
    "Italia",
    "Italia",
    "Germania",
    "Afghanistan",
    "Italia"
]

While what I am looking for is to get a format like this. Regardless of different values how do I add a propriety name in roder to get something along those lines?

var data = [{
    "name": "Tokyo",
    "data": 3.0
}, {
    "name": "NewYork",
    "data": 2.0
}, {
    "name": "Berlin",
    "data": 3.5
}, {
    "name": "London",
    "data": 1.5
}];

print_r($periodi);

Array ( [0] => Moderno [1] => Contemporaneo [2] => Contemporaneo [3] => Contemporaneo [4] => Contemporaneo )

I have another array with different data but still the format is wrong:

Array ( [francese] => Array ( [maschio] => Array ( [0] => 1 ) [femmina] => Array ( [0] => 1 ) ) [chimica] => Array ( [maschio] => Array ( [0] => 1 [1] => 1 ) ) [fisica] => Array ( [maschio] => Array ( [0] => 1 [1] => 1 ) [femmina] => Array ( [0] => 1 ) ) [scienze] => Array ( [maschio] => Array ( [0] => 1 ) ) [inglese] => Array ( [maschio] => Array ( [0] => 1 ) ) [spagnolo] => Array ( [maschio] => Array ( [0] => 1 ) ) [italiano] => Array ( [femmina] => Array ( [0] => 1 ) ) )

 {
        "maschio": [
            true
        ],
        "femmina": [
            true
        ]
    },
    {
        "maschio": [
            true,
            true
        ]
    },
    {
        "maschio": [
            true,
            true
        ],
        "femmina": [
            true
        ]
    },
    {
        "maschio": [
            true
        ]
    },
    {
        "maschio": [
            true
        ]
    },
    {
        "maschio": [
            true
        ]
    },
    {
        "femmina": [
            true
        ]
    }
]

Answer 1

    $jsonArr = array();
    foreach($periodi as $key => $val){
        $jsonArr[$key]['name'] = $val;
        $jsonArr[$key]['data'] = $key; //there is no source for priority 
          //in your array so i just put $key as priority variable
    }

    json_encode($jsonArr);

Answer 2

You should make your array like this ...

Array
(
    [0] => Array
        (
            ['name'] => 'Tokyo'
            ['data'] => 3
        )

    [1] => Array
        (
            ['name'] => 'NewYork'
            ['data'] => 2
        )
)

How to make the array ?

$final_array = array();
foreach($data as $key=>$value)
{
    $final_array[]=array(
                "name"=>$key,
                "data"=>$value
               );
}

Then you just need to json_encode the $final_array .

Answer 3

PHP code demo

<?php
$array=
    [
    "Moderno",
    "Contemporaneo",
    "Contemporaneo",
    "Contemporaneo",
    "Contemporaneo"
];

$array=array_count_values($array);
$result=array();
foreach($array as $key => $value)
{
    $result[]=array("name"=>$key,"data"=>$value);
}
print_r(json_encode($result));