如何使用WSO2 DSS从mongodb获取第二条记录？

Question

I have connected the MongoDB successfully and now have also accessed the mongodb records using WSO2 DSS tryit tool. Here is what I received while accessing the records:

As you see I get the output as:

 <data>{ "_id" : { "$oid" : "589d96d841a427c4389a38d5"} , "domain" : "yahoo.com" , "emails" : [ { "email" : "fghj"} , { "email" : "dfghjk"}]}</data>
   <data>{ "_id" : { "$oid" : "589d993a41a427c4389a38d8"} , "domain" : "yahoo.com" , "emails" : [ { "email" : "fghj"} , { "email" : "dfghjk"}]}</data>

As you see there is _id in the output. I intent to remove it. But could not.

The query I placed in WSO2 DSS is like this:

collect.find({"domain":#},{"_id":0})

Where collect is the name of my collect of mongodb.

Here s the json structure that I have placed in the ooutput mapping area on WSO2 DSS:

{"entries":{"data":$document}}

I do not understand what to do in order to exclude or neglect the _id field and get only the domain part as it is in my output window.
Kindly suggest me what I can do to make my work done.

Answer 1

I'm totally new to WSO2, but we have the same surname ;) so I'll try to help.

I'm not sure you can remove the _id field, but I think the correct way to handle this is to create a proxy service, that runs through the json and returns only the fields that you want.

Hope it helps.