如何从SQL中的某些ID获取最小值和最大值

Question

I got a database with certain colums I am working with the adress and the time(unixtime) but I need to calculate from all colums with the same record(value) from the colum adres the time between the first and the last one

So lets say adress x has 3 entries, then I want to sort the time from min to max. So I need to sort on adress, then time from min to max/max to min so I can calculate how long the person stayed there (time)

Answer 1

I thin, you want group by and the difference in times:

select address, min(from_unixtime(time)), max(from_uixtime(time)),
       ( max(from_unixtime(time)) - min(from_uixtime(time)) ) as diff
from sensordata1
group by address;

Answer 2

    SELECT address
        , MAX(FROM_Unixtime(time))  as myMaxTime
        , MIN(FROM_Unixtime(time)) as myMinTime
        , TIMEDIFF(MAX(FROM_Unixtime(time)), MIN(FROM_Unixtime(time)))
    FROM sensordata1
    GROUP BY  address

If you do not want to return the entire dataset