[英]json2html python lib is not working
I'm trying to create new json file with my custom json input and converting JSON to HTML format and saving into .html file. 我正在尝试使用我的自定义json输入创建新的json文件,并将JSON转换为HTML格式并保存到.html文件中。 But I'm getting error while generating JSON and HTML file. 但是我在生成JSON和HTML文件时遇到错误。 Please find my below code - Not sure what I'm doing wrong here: 请找到我的下面代码 - 不确定我在这里做错了什么:
#!/usr/bin/python
# -*- coding: utf-8 -*-
from json2html import *
import sys
import json
JsonResponse = {
"name": "json2html",
"description": "Converts JSON to HTML tabular representation"
}
def create(JsonResponse):
#print JsonResponse
print 'creating new file'
try:
jsonFile = 'testFile.json'
file = open(jsonFile, 'w')
file.write(JsonResponse)
file.close()
with open('testFile.json') as json_data:
infoFromJson = json.load(json_data)
scanOutput = json2html.convert(json=infoFromJson)
print scanOutput
htmlReportFile = 'Report.html'
htmlfile = open(htmlReportFile, 'w')
htmlfile.write(str(scanOutput))
htmlfile.close()
except:
print 'error occured'
sys.exit(0)
create(JsonResponse)
Can someone please help me resolve this issue. 有人可以帮我解决这个问题。
Thanks! 谢谢!
First, get rid of your try
/ except
. 首先,摆脱你的try
/ except
。 Using except
without a type expression is almost always a bad idea. 使用except
没有类型表达式的情况几乎总是一个坏主意。 In this particular case, it prevented you from knowing what was actually wrong. 在这种特殊情况下,它阻止您了解实际上是错误的。
After we remove the bare except:
, we get this useful error message: 删除except:
的裸露之后,我们得到了这个有用的错误消息:
Traceback (most recent call last):
File "x.py", line 31, in <module>
create(JsonResponse)
File "x.py", line 18, in create
file.write(JsonResponse)
TypeError: expected a character buffer object
Sure enough, JsonResponse
isn't a character string ( str
), but is a dictionary. 果然, JsonResponse
不是字符串( str
),而是字典。 This is easy enough to fix: 这很容易修复:
file.write(json.dumps(JsonResponse))
Here is a create()
subroutine with some other fixes I recommend. 这是一个create()
子例程,我建议使用其他一些修复程序。 Note that writing the dumping the JSON followed immediately by loading the JSON is usually silly. 请注意,通过加载JSON立即编写转储JSON后通常是愚蠢的。 I left it in assuming that your actual program does something slightly different. 我假设你的实际程序做了一些略微不同的事情。
def create(JsonResponse):
jsonFile = 'testFile.json'
with open(jsonFile, 'w') as json_data:
json.dump(JsonResponse, json_data)
with open('testFile.json') as json_data:
infoFromJson = json.load(json_data)
scanOutput = json2html.convert(json=infoFromJson)
htmlReportFile = 'Report.html'
with open(htmlReportFile, 'w') as htmlfile:
htmlfile.write(str(scanOutput))
The error is while writing to the JSON file. 写入JSON文件时出错。 Instead of file.write(JsonResponse)
you should use json.dump(JsonResponse,file)
. 而不是file.write(JsonResponse)
你应该使用json.dump(JsonResponse,file)
。 It will work. 它会工作。
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