带烧瓶的后请求错误

Question

I'm trying to make a CRUD REST API with Flask en SQlALchemy. 我正在尝试使用Flask en SQlALchemy制作CRUD REST API。 I'm making request with the curl command on the linux shell but I cant get it to work. 我在linux shell上使用curl命令发出请求，但无法正常工作。 If I open a python shell and add the things manually they get added to the database. 如果我打开python shell并手动添加东西，它们将被添加到数据库中。

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 3.2 Final//EN">
<title>400 Bad Request</title>
<h1>Bad Request</h1>
<p>The browser (or proxy) sent a request that this server could not understand.</p>

@app.route('/create', methods = ['POST'])
def create():
    username = request.form['username']
    age = request.form['age']
    email = request.form['email']

curl -X POST -F 'username=Juliana' -F 'age=87' -F 'email=juliana@.com' http://localhost:5000/create

Answer 1

the issue is that Flask raises an HTTP error when it fails to find a key in the args and form dictionaries. 问题是，当Flask在args中找不到键并形成字典时，它会引发HTTP错误。 What Flask assumes by default is that if you are asking for a particular key and it's not there then something got left out of the request and the entire request is invalid. Flask默认情况下假设的是，如果您要的是特定密钥，而该密钥不存在，则请求中遗漏了某些内容，整个请求均无效。

check: 校验：

change your create view to the following code and check output: 将您的create视图更改为以下代码并检查输出：

@app.route('/create', methods = ['POST'])
def create():
    username = request.form.get('username', '')
    age = request.form.get('age', '')
    email = request.form.get('email', '')
    print username, age, email

    # dbcreate = Profile(username, age, email)
    # db.session.add(dbcreate)
    # db.session.commit()
    # print 'User Created'

带烧瓶的后请求错误

问题描述

1 个解决方案

解决方案1
0 2017-04-14 05:04:05

带烧瓶的后请求错误

问题描述

1 个解决方案

解决方案1 0 2017-04-14 05:04:05

解决方案1
0 2017-04-14 05:04:05