删除字符串JavaScript正则表达式中的字符

Question

I have a chain like this of get page

file.php?Valor1=one&Valor2=two&Valor3=three

I would like to be able to delete the get request parameter with only having the value of it. for example , remove two Result

file.php?Valor1=one&Valor3=three

Try with

stringvalue.replace(new RegExp(value+"[(&||\s)]"),'');

Answer 1

Here's a regular expression that matches an ampersand ( & ), followed by a series of characters that are not equals signs ( [^=]+ ), an equals sign ( = ), the literal value two and either the next ampersand or the end of line (&|$) :

/&[^=]+=two(&|$)/

 let input = 'file.php?&Valor1=one&Valor2=two&Valor3=three'; let output = input.replace(/&[^=]+=two/, ''); console.log(output); 

If you're getting the value to be removed from a variable:

 let two = 'two'; let re = RegExp('&[^=]+=' + two + '(&|$)'); let input = 'file.php?&Valor1=one&Valor2=two&Valor3=three'; let output = input.replace(re, ''); console.log(output); 

In this case, you need to make sure that your variable value does not contain any characters that have special meaning in regular expressions. If that's the case, you need to properly escape them.

Update
To address the input string in the updated question (no ampersand before first parameter):

 let one = 'one'; let re = RegExp('([?&])[^=]+=' + one + '(&?|$)'); let input = 'file.php?Valor1=one&Valor2=two&Valor3=three'; let output = input.replace(re, '$1'); console.log(output); 

Answer 2

You can use RegExp constructor, RegExp , template literal &[a-zA-Z]+\\\\d+=(?=${remove})${remove}) to match "&" followed by "az", "AZ", followed by one or more digits followed by "" , followed by matching value to pass to .replace()

 var str = "file.php?&Valor1=one&Valor2=two&Valor3=three"; var re = function(not) { return new RegExp(`&[a-zA-Z]+\\\\d+=(?=${not})${not}`) } var remove = "two"; var res = str.replace(re(remove), ""); console.log(res); var remove = "one"; var res = str.replace(re(remove), ""); console.log(res); var remove = "three"; var res = str.replace(re(remove), ""); console.log(res); 

Answer 3

I think a much cleaner solution would be to use the URLSearchParams api

var paramsString = "Valor1=one&Valor2=two&Valor3=three"
var searchParams = new URLSearchParams(paramsString);

//Iterate the search parameters.
//Each element will be [key, value]
for (let p of searchParams) {
    if (p[1] == "two") {
        searchParams.delete(p[0]);
    }
}

console.log(searchParams.toString()); //Valor1=one&Valor3=three