如何避免Ajax跨域请求上的JavaScript错误

Question

How is it possible to avoid or catch the javascript error without the script to break?

returns error (empty output)

$.ajax({
    type : 'GET',
    dataType : 'jsonp',
    url : '//cvrapi.dk/api?search=dsfsdfsd&country=dk',
    success : function(res){
        if(success){
            success(res);
        }
    }
});

no error is returned (with output)

$.ajax({
    type : 'GET',
    dataType : 'jsonp',
    url : '//cvrapi.dk/api?search=test&country=dk',
    success : function(res){
        if(success){
            success(res);
        }
    }
});

Answer 1

The first one returns a 404 status on the request so you can use fail() to catch the bad request and check status:

 $.ajax({ type: 'GET', dataType: 'jsonp', url: '//cvrapi.dk/api?search=dsfsdfsd&country=dk', success: function(res) { if (success) { success(res); } } }).fail(function(err) { console.log('Something went wrong'); // check various status as documented by API if (err.status === 404) { console.log('Not found') } }); 

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>