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PHP的; 在循环中添加到多维数组的值

[英]php; Adding to the value of a multidimensional array in a loop

So I'm trying to make an array for stat growths in a fake rpg. 因此,我正在尝试为伪造的rpg创建一个统计数据增长数组。 It looks like this. 看起来像这样。

// base array
// $base: starting base stats
// $growth: growth rate per rng
$growths = array(
    'HP' => array (70 => 20),
    'STR' => array (50 => 7),
    'MAG' => array (35 => 2),
    'SKL' => array (45 => 6),
    'SPD' => array (50 => 8),
    'LCK' => array (55 => 5),
    'DEF' => array (45 => 6),
    'RES' => array (15 => 4),
);    

//rng calculator
for ($x = 0; $x <= 20; $x++) {
    foreach ($growths as $stat_name => $info) {
        $roll = rand(0,100);
        foreach ($info as $growth => $base) {
            if ($roll <= $growth) {
                $info[$growth] = ++$base;
                print "(UP!) ";
            }
            echo "$stat_name: $base<br/ >";
        }
    }
} 

My only issue is that the new $base value after the rng calculator refuses to store in the original array. 我唯一的问题是rng calculator拒绝存储在原始数组后的新$base值。 Am I doing something wrong, or do I just need to rebuild the array from scratch and try something else? 我是在做错什么,还是只需要从头开始重建阵列并尝试其他操作? Any help would be appreciated! 任何帮助,将不胜感激!

In your first foreach loop, you assign the key of $growths to $stat_name and the value to $info . 在你的第一个foreach循环,分配的关键$growths$stat_name和价值$info These are temporary variables. 这些是临时变量。 If you change them, the original array is not affected. 如果更改它们,则原始阵列不受影响。

// This won't work because $info is temporary.
$info[$growth] = ++$base;

Instead, simply refer to the original array: 相反,只需引用原始数组即可:

// Do this instead.
$growths[$stat_name][$growth] = ++$base;

use reference 使用参考

just use foreach ($growths as $stat_name => &$info) to replace conrresponding line in your code. 只需使用foreach ($growths as $stat_name => &$info)来替换代码中的相应行。

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