如何使用JGit检出某个文件夹

Question

FetchResult fr = git.fetch().setCredentialsProvider(credentials).setCheckFetchedObjects(true).Call();
git.checkout().setCreateBranch(true).setName("origin/" + branchName).setStartPoint("origin/" + branchName + "path/to/folder").call()

This is the code I'm using to check out a single folder from a remote repository. Equivalent git commands are:

git fetch origin
git checkout origin/branch -- path/to/folder

But, the Java code doesn't work for me, I was only able to initialise the local repository and configure remote repository. The checkout didn't work and I couldn't find out what mistake I'm making.

Answer 1

Try making changes in the checkout part like this

"origin/"

and give it a try.

Otherwise you want to do is a sparse checkout

How do I implement sparse checkout in JGit?

Answer 2

In order to check out a particular folder with JGit (a sparse checkout), you need to tell the CheckoutCommand which folder to check out.

For example:

git.checkout().setName( "branch-to-check-out" ).addPath( "path/to/folder" ).call();

addPath() can be called multiple times to check out each of the given paths. The path is interpreted relative to the work directory.