neo4j StatementResult到scala中的json

Question

I'm new to scala. I'm building a REST-API to query several services, one of them Neo4j, using scala-2.11 I'm reading a neo4j output as StatementResult (org.neo4j.driver.v1 public interface StatementResult extends Iterator), this way:

val recordsList = session.run(queryNeo4j)
println("recordsList:" +recordsList.list())

The println gives this output:

recordsList:[Record<{n: node<6103>}>, Record<{n: node<6104>}>]

and trying to convert it into a json to send in the response, using play-json. At first, I've tried this:

val recordJ = Json.parse(recordList)

but it's not working. I've also tried this:

while (recordsList.hasNext() ) {
          val record = recordsList.next()
          println("record: " +record)
          val recordJ = Json.parse(record)
        }

But it's not working either.I get this error:

error: overloaded method value parse with alternatives:
   [INFO]   (input: Array[Byte])play.api.libs.json.JsValue <and>
   [INFO]   (input: java.io.InputStream)play.api.libs.json.JsValue <and>
   [INFO]   (input: String)play.api.libs.json.JsValue
   [INFO]  cannot be applied to (org.neo4j.driver.v1.Record)
   [INFO]           val recordJ = Json.parse(record)
   [INFO]

Could someone please help me to get a json with the recordsList?

Thank you

Answer 1

The easiest way would be to turn the statement result into a deep list of objects.

val data = result.list(_.asMap())

And then format the result as JSON.

See the javadocs for each method.

• StatementResult
• Record