[英]Pass data between two php pages while both are opened
I have some PHP files in some project. 我在某些项目中有一些PHP文件。 This project contains two main parts. 该项目包含两个主要部分。 These are "Admin" and "user". 它们是“管理员”和“用户”。 My project folder is much likely: 我的项目文件夹很可能是:
C:\xampp\htdocs\project
Say I have an admin panel page named "admin_panel.php" in such directory C:\\xampp\\htdocs\\project\\admin\\admin_panel.php
假设我在这样的目录C:\\xampp\\htdocs\\project\\admin\\admin_panel.php
有一个名为“ admin_panel.php”的管理面板页面
as well as I have also a user page named " user_file.php " in such directory 在该目录中还有一个名为“ user_file.php ”的用户页面
C:\xampp\htdocs\project\user\user_file.php
Both files are opened in two browsers say in chrome and firefox. 在chrome和firefox这两个浏览器中都打开了这两个文件。
Now I want to pass some notification with yes/no button from " admin_panel.php " to " user_file.php ". 现在,我想通过“是/否”按钮将一些通知从“ admin_panel.php ”传递到“ user_file.php ”。 Whenever " user_file.php " get that content, one can press yes/no and this data is needed to send to " admin_panel.php " to take proper action. 只要“ user_file.php ”获得该内容,就可以按“是/否”,并且需要将该数据发送到“ admin_panel.php ”以采取适当的措施。
How these can be done. 这些怎么做。 Any answer will be appreciated. 任何答案将不胜感激。 Thanks in advance :) 提前致谢 :)
You could use "Sessions" with PHP, which you can update with AJAX 您可以在PHP中使用“会话”,然后可以使用AJAX更新
$.ajax({
method: 'POST',
url: 'somephp.php',
data: {
'someinfo': info,
'ajax': true
},
success: function(data) {
//if you want to do anything else
}
});
PHP Code: PHP代码:
<?php
session_start();
$_SESSION["info"] = $_POST["info"];
//or what ever
?>
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