[英]pthread synchronization using mutex
I was trying to create 2 threads and calling the same function which increments a counter "count" from a for loop. 我试图创建2个线程并调用相同的函数,该函数从for循环中增加计数器“ count”。 But every time I run this code the value of the counter is different.
但是每次我运行此代码时,计数器的值都不同。 I try to use mutex to have synchronization between threads when they increment the global static variable "count" but still value is different.
当它们增加全局静态变量“ count”但值仍然不同时,我尝试使用互斥锁在线程之间进行同步。
static int count;
pthread_mutex_t count_mutex;
void increment()
{
pthread_mutex_lock(&count_mutex);
count++;
pthread_mutex_unlock(&count_mutex);
}
void *myThreadFun1(void *var)
{
printf("Thread1\n");
for(int i=0; i< 10000;i++)
{
increment();
}
return;
}
int main()
{
pthread_t tid1;
pthread_t tid2;
pthread_create(&tid1, NULL, myThreadFun1, NULL);
// sleep(1);
pthread_create(&tid2, NULL, myThreadFun1, NULL);
pthread_join(tid1, NULL);
pthread_join(tid2, NULL);
printf("\n%d",count);
exit(0);
}
Output is never 20000 if I don't sleep between threads. 如果我不睡在线程之间,则输出永远不会是20000。
In java there is "synchronized" keyword we can use, but how to achieve same in C ? 在Java中,我们可以使用“ synchronized”关键字,但是如何在C中实现相同的关键字?
pthread_mutex_t requires initialization before use. pthread_mutex_t在使用前需要进行初始化。 It must start unlocked and unbound.
它必须开始解锁并解除绑定。 There is a call, pthread_mutex_init(&theMutex) that can do this, or a predefined value can be assigned for static init: PTHREAD_MUTEX_INITIALIZER
有一个调用pthread_mutex_init(&theMutex)可以执行此操作,或者可以为静态init分配预定义的值:PTHREAD_MUTEX_INITIALIZER
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