将文本拆分为单词，但将逗号视为单词

Question

I would like to get each word of this text but need to consider comma as a separate word, in PHP:

My input text:

Lorem ipsum dolor sit amet, consectetuer adipiscing elit.

My wanted array:

array[0] => "Lorem"
array[1] => "ipsum"
array[2] => "dolor"
array[3] => "sit"
array[4] => "amet"
array[5] => ","
array[6] => "consectetuer"
array[7] => "adipiscing"
array[8] => "elit"
array[9] => "."

What I get with explode(" ", $text) is:

array[0] => "Lorem"
array[1] => "ipsum"
array[2] => "dolor"
array[3] => "sit"
array[4] => "amet,"
array[5] => "consectetuer"
array[6] => "adipiscing"
array[7] => "elit."

Answer 1

You could replace the comma with a space+comma+space ',' -> ' , '

$newSentence = str_replace("," , " , " , $theSentence);  
$arr = preg_split('/[\s]+/', $newSentence);

Answer 2

Try below,

preg_match_all('/([\w]+)([\,\.])?/', "Lorem ipsum dolor sit amet, consectetuer adipiscing elit.",$match);

$arr = array_merge($match[1],array_filter($match[2]));
print_r($arr);

Answer 3

You should use preg_match_all() without any capture groups or lookarounds for best efficiency.

Code: ( Demo )

$string='Lorem ipsum dolor sit amet, consectetuer adipiscing elit.';
var_export(preg_match_all('/[a-z]+|\S/i',$string,$out)?$out[0]:'fail');

Output:

array (
  0 => 'Lorem',
  1 => 'ipsum',
  2 => 'dolor',
  3 => 'sit',
  4 => 'amet',
  5 => ',',
  6 => 'consectetuer',
  7 => 'adipiscing',
  8 => 'elit',
  9 => '.',
)

\w can be used to match az , AZ , 0-9 , and _ but in your sample only letters exist.

If you are including apostrophes, you can use $pattern='/[az\']+|\S/i' but future adjustments are decisions for you to make.

The \S in the second alternative is any non-whitespace character -- this collects all of the punctuation characters (one at a time) that the first alternative lets through.

The i flag on the pattern dictates that [az] will act like [A-Za-z] .