[英]Regex pattern to exclude numbers and special characters in a string
Regex pattern to exclude numbers and special characters in a string. 正则表达式模式可排除字符串中的数字和特殊字符。
I need to exclude numbers and special characters in the below string. 我需要在下面的字符串中排除数字和特殊字符。
A service with name "11.KGGS.003022..CBCL.." is already active between Mon Apr 17 00:00:00 2017 and Thu Dec 30 00:00:00 9999.
在2017年4月17日星期一00:00:00至12月30日星期四00:00:00 9999之间,名称为“ 11.KGGS.003022..CBCL ..”的服务已处于活动状态。
i need to use the pattern in tableau and regex[^0-9]
is not working in it. 我需要在Tableau中使用该模式,而
regex[^0-9]
在其中不起作用。 Kindly help me out. 请帮我。
you can use replaceAll
like so : 您可以这样使用
replaceAll
:
str = str.replaceAll("[0-9!@#$%^&*()_+\\-=\\[\\]{};':\"\\\\|,.<>\\/?]", "");
Output 输出量
A service with name KGGSCBCL is already active between Mon Apr and Thu Dec
I'm not sure if the space consider like a special character or not, if yes you can use this instead : 我不确定空格是否认为是特殊字符,如果是,则可以改用:
str = str.replaceAll("[0-9!@#$%^&*()_+\\-=\\[\\]{};':\"\\\\|,.<>\\/?\\s\\n]", "");
//------------------------------------------------Space and back line ^--^
Output 输出量
AservicewithnameKGGSCBCLisalreadynactivebetweenMonAprandThuDec
In case you want to make only one space between each word you can use this : 如果您只想在每个单词之间留一个空格,可以使用以下命令:
str = str.replaceAll("[0-9!@#$%^&*()_+\\-=\\[\\]{};':\"\\\\|,.<>\\/?]", "").
replaceAll("\\s+", " ");
//------------------^^^^----^---------replace multiple spaces with only one
Output 输出量
A service with name KGGSCBCL is already nactive between Mon Apr and Thu Dec
exclude numbers and special characters the rest should be only the alphabetic [a-zA-Z]
, so you can use also this : 排除数字和特殊字符 ,其余应仅是字母
[a-zA-Z]
,因此您也可以使用以下代码:
str = str.replaceAll("[^a-zA-Z]", "");
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.