[英]instantiating parameterized class
Just wondering if this is the right way to do it. 只是想知道这是否是正确的方法。 I want to construct instances of my parametrized class where one of the instance variables is a generic type. 我想构造我的参数化类的实例,其中实例变量之一是泛型类型。 The code below works but I get a lot of warnings in the main method "SomeObject is a raw type. References to generic type SomeObject should be parameterized". 下面的代码有效,但是在主要方法“ SomeObject是原始类型。应该对通用类型SomeObject的引用进行参数设置”时,我会收到很多警告。
public class SomeObject<T> {
private String description;
private T value;
public SomeObject(String description, T value) {
this.description = description;
this.value = value;
}
public static void main(String args[]){
List <SomeObject> objectList = new ArrayList<SomeObject>();
objectList.add(new SomeObject("Object 1: ", true));
objectList.add(new SomeObject("Object 2: ", 888.00));
objectList.add(new SomeObject("Object 3: ", "another object"));
objectList.add(new SomeObject("Object 4: ", '4'));
for (SomeObject object : objectList){
System.out.println(object.getDescription() + object.getValue());
}
}
} }
The code below works but I get a lot of warnings in the main method "Object is a raw type. References to generic type Object should be parameterized". 下面的代码可以工作,但是我在主要方法“对象是原始类型。应该对通用类型对象的引用进行参数化”方面收到很多警告。
the warning is because you haven't specified the type arguments when constructing the SomeObject
. 警告是因为在构造SomeObject
时没有指定类型参数。 ie. 即。
it should be: 它应该是:
List<SomeObject<?>> objectList = new ArrayList<>();
objectList.add(new SomeObject<Boolean>("Object 1: ", true));
objectList.add(new SomeObject<Double>("Object 2: ", 888.00));
objectList.add(new SomeObject<String>("Object 3: ", "another object"));
objectList.add(new SomeObject<Character>("Object 4: ", '4'));
When you have a SomeObject
without a type argument (the part in the square brackets), that is called a raw type , and it's the same as using the erasure of SomeObject
. 当您拥有不带类型SomeObject
(方括号中的部分)时,这称为原始类型 ,这与使用擦除SomeObject
。 (Basically, the erasure means it's non-generic.) (基本上,擦除表示它是非通用的。)
You also need to provide a type argument to the SomeObject
part of the List
. 您还需要为List
的SomeObject
部分提供类型参数。 Here I've used a wildcard, which means the list can hold any type of SomeObject
, but once we put a SomeObject
in to the list we don't know what their original type argument was anymore: 在这里,我使用了通配符,这意味着列表可以容纳任何类型的SomeObject
,但是一旦将SomeObject
放入列表中,我们就不知道它们原来的类型参数是什么了:
List<SomeObject<?>> objectList = new ArrayList<SomeObject<?>>();
objectList.add(new SomeObject<Boolean>("Object 1: ", true));
objectList.add(new SomeObject<Double>("Object 2: ", 888.00));
objectList.add(new SomeObject<String>("Object 3: ", "another object"));
objectList.add(new SomeObject<Character>("Object 4: ", '4'));
for (SomeObject<?> object : objectList) {
...;
}
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