将 shared_ptr 与 char* 一起使用

Question

I can not create:

shared_ptr<char> n_char = make_shared<char>(new char[size_]{});

How can I create

char* chr = new char[size_]{}; 

using modern pointers?

Answer 1

shared_ptr n_char = make_shared(new char[size_]{});

make_shared calls new inside, so you never use both. In this case you only call new , because make_shared does not work for arrays.

However, you still need to make it call the right delete:

Before C++17 :

You need to specify the deleter explicitly.

std::shared_ptr<char> ptr(new char[size_], std::default_delete<char[]>());

Since C++17 :

shared_ptr gains array support similar to what unique_ptr already had from the beginning:

std::shared_ptr<char[]> ptr(new char[size_]);

---

Be aware that done this simple way you are not tracking length and in multi-threaded environment not synchronizing. If you need the buffer modifiable, making shared pointer to std::string , or struct with std::string and std::mutex in it, will add a level of indirection, but will be otherwise more convenient to use.

Answer 2

You could use std::default_delete specialized for arrays

std::shared_ptr<char> ptr(new char[size_], std::default_delete<char[]>());

See std::default_delete docs . While std::unique_ptr uses default_delete by default when no other deleter is specified and has a partial specialization that handles array types:

std::unique_ptr<char[]> ptr(new char[size_]);

With std::shared_ptr you need to select it manually by passing a deleter to the constructor.

Edit: Thanks to Jan Hudec, c++17 includes a partial specialization for array types as well:

std::shared_ptr<char[]> ptr(new char[size_]);  // c++17

Answer 3

对于简单的字符缓冲区：

std::shared_ptr<char> ptr( (char*)operator new( buffer_size_here ) );