Excel 公式返回值而不是 TRUE 或 False

Question

I am very newbie in excel, I wanted to make my formula to return matched value instead of TRUE/FALSE

=NOT(NOT(SUM(--NOT(ISERR(SEARCH($D$2:$D$21;$B2))))))

is there anyway this formula can be revised to return like for example: found word "wow" and return the word into the cell instead of TRUE/FALSE?

thank you

Answer 1

您可以使用 IF 函数：

=IF(logical_test, CONCAT("Found word", $YourWord), "Not found")

Answer 2

Use the =IF function.

=IF(condition; value if true; value if false)

• condition is your condition to test. For example $A$1 < 5
• value if true is a value returned if condition is true
• value if false opposite to previous part, this is a value returned if condition is false.

Following formula will return a $A$1 cell value if less than 5 and too big literally if $A$1 's value is bigger or equal to 5:

=IF($A$1<5; $A$1; "too big")

Just combine it with your condition.

Answer 3

This will help You Remember the " Text " must be in " "

=IF(ISNUMBER(SEARCH(substring;"WOW")); "Yes"; "No")

The Value will be only Yes or No , You may change that

Answer 4

There are two cases and I'm not sure which one you need

(1) You have a word like WOW, and you want to find matches in a list of strings like BOWWOW

(2) You have a word like WOW, and you want to find matches for part of it in a list of substrings like OW

The easiest way to do the first one is to use MATCH with a wildcard

=INDEX($D$2:$D$21,MATCH("*"&B2&"*",$D$2:$D$21,0))

For the second one you would need to modify your formula a bit

=INDEX($D$2:$D$21,MATCH(0,(ISERROR(SEARCH($D$2:$D$21,$B$2))+($D$2:$D$21="")),0))

or

=INDEX($D$2:$D$21,MATCH(1,ISNUMBER(SEARCH($D$2:$D$21,$B$2))*($D$2:$D$21<>""),0))

the last two entered as array formulae using Ctrl Shift Enter