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如何在JPA信息库中获取链接表的ID

[英]How to get the ID of linked table in JPA repository

I have the following code in which I want to get the id of rider, But I have no idea how to do this , Actually rider is the type of User which is linked to RiderLocation table , When I change the type of rider to User then I cant send the id in parameter of URL like this 我有以下代码,我想获取骑手的ID,但是我不知道该怎么做,实际上骑手是链接到RiderLocation表的User类型,当我将骑手的类型更改为User时,我无法像这样在URL参数中发送ID

http://localhost:3000/api/riderLocations/search/findByRider?rider_id=3 HTTP://本地主机:3000 / API / riderLocations /搜索/ findByRider rider_id = 3

Code is below 代码如下

RiderLocation.java RiderLocation.java

@Entity
public class RiderLocation implements Serializable {

    private static final long serialVersionUID = 1L;
        @Id
        @GeneratedValue(strategy = GenerationType.IDENTITY)
        private Long id;

        @ManyToOne
        private User rider;

        private Double latitude;
        private Double longitude;

        public Long getId() {
            return id;
        }

        public void setId(Long id) {
            this.id = id;
        }
        public User getRider() {
            return rider;
        }
        public void setRider(User rider) {
            this.rider = rider;
        }
        public Double getLatitude() {
            return latitude;
        }

        public void setLatitude(Double latitude) {
            this.latitude = latitude;
        }

        public Double getLongitude() {
            return longitude;
        }
      public void setLongitude(Double longitude) {
            this.longitude = longitude;
        }
    }

RiderLocationRepository RiderLocationRepository

public interface RiderLocationRepository extends JpaRepository<RiderLocation, Long>{

    @Query("select r.latitude,r.longitude from RiderLocation r ")
    ArrayList<Object[]>   findAllRidersLocation();
    RiderLocation findByRider(@Param("rider_id") Long rider);

}

The problem is solved now the only mistake is I wrote 现在问题解决了,唯一的错误是我写的

findByRider(@Param("rider_id") Long rider);

instead of : 代替 :

findByRiderId(@Param("rider_id") Long rider);

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