Android套接字连接丢失？

Question

I´m playing around with Sockets and wrote a test app to send text messages to a server running on my PC and have the server display them. I wrote a similar client in Java to test it and it worked. But now in Android, it seems to establish a connection to the server, but it only recieves the first message and subsequent messages won´t show up. I thought, maybe the thread is only executing once, but that´s not the case since logcat recognizes the button presses.

Android

public class MainActivity extends AppCompatActivity {

 @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        final EditText enter = (EditText) findViewById(R.id.editText1);
        final Button button = (Button) findViewById(R.id.button);
        final String fromUser = null;
        button.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View v) {

                new Thread(new Runnable(){
                    @Override
                    public void run(){
                        PrintWriter out = null;
                        BufferedReader in = null;
                        Socket clientSocket = null;
                        try {
                            clientSocket = new Socket("192.168.178.41", 5959);
                            out = new PrintWriter(clientSocket.getOutputStream(), true);
                            in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
                        } catch (IOException e) {
                            e.printStackTrace();
                            Log.d("---","cant make a connection");
                        }
                        String fromUser = enter.getText().toString();
                        if (fromUser != null) {
                            System.out.println("Client: " + fromUser);
                            out.println(fromUser);
                        }
                    }

                }).start();
            }
        });
    }
}

Server

public class Server {

public static void main(String[] args) {
        System.out.println("Starting server!");
        PrintWriter out = null;
        BufferedReader in = null;
        try{
             ServerSocket serverSocket = new ServerSocket(5959);
             Socket clientSocket = serverSocket.accept();
             out = new PrintWriter(clientSocket.getOutputStream(), true);
             in = new BufferedReader(new InputStreamReader(clientSocket.getInputStream()));
             System.out.println("Established a connection with a user!");
        } catch (IOException e) {
             e.printStackTrace();
        }
        String inputLine;
        String outputLine = "Hey Client from Server!";

        out.println(outputLine);

        try {
        while ((inputLine = in.readLine()) != null) {
            out.println(inputLine);
            System.out.println("Client: " + inputLine);
            if (inputLine.equals("quit"))
                break;
        }
        } catch (IOException e) {
        e.printStackTrace();
        }
    }   

}

I cant figure out what is causing the problem, but its for sure a silly mistake...

Answer 1

1. Your client is creating one connection and sending only one message per click.
2. Your server is only accepting one connection.
3. Your client is never closing the socket. Instead it is leaking it.
4. Your server is therefore never getting out of its read loop.
5. Even if it did, it would never accept a new client because of (2).
6. It will never received more than one message inside the loop because of (1).

In short your code makes no sense whatsoever.