[英]Get Value(XPath) using XSL Variable - xslt
While trying to parse the below xml
, 尝试解析以下
xml
,
<root>
<SelectValue>One</SelectValue> <!-- Tends to Vary -->
<SubRoot> <!-- Iterate elements inside it using [ SelectValue] -->
<One>One</One>
<Two>Two</Two>
<Three>Three</Three>
</SubRoot>
</root>
with below xsl
, 低于
xsl
,
<xsl:template match="/root">
<xsl:variable name="columns" select="SelectValue"/>
<xsl:for-each select="SubRoot"> -->
<tr>
<td>
<xsl:value-of select="SubRoot/@*[local-name()=$columns]"/>
</td>
</tr>
</xsl:for-each>
Retrieves an empty html-tags
while i expect something like below, 检索空的
html-tags
而我期望如下所示,
<table>
<thead>
<th>One</th>
</thead>
<tbody>
<tr>
<td>one</td>
</tr>
<tbody>
</table>
I am trying to pass the value inside <SelectValue>
to get the nodes inside <SubRoot>
我试图在
<SelectValue>
内部传递值以获取<SubRoot>
内部的节点
Any thoughts here ? 这里有什么想法吗?
I do not recognize the error message you quote (it doesn't even seem to be English), but I do get an error when trying to run your code. 我无法识别您引用的错误消息(它甚至似乎都不是英语),但是在尝试运行您的代码时确实出现了错误。 The reason is that your variable name is invalid;
原因是您的变量名无效; you need to change:
您需要更改:
<xsl:variable name="$columns" select="..."/>
to: 至:
<xsl:variable name="columns" select="..."/>
Use the $
prefix when referring to the variable, not when defining it. 引用变量时使用
$
前缀,而不是在定义变量时使用。
Note also that an XPath expression beginning with a /
is an absolute path , starting at the root node. 还要注意,以
/
开头的XPath表达式是绝对路径 ,从根节点开始。 Therefore none of your select
expressions - with the exception of /root
- will select anything. 因此,除了
/root
外,所有select
表达式都不会选择任何内容。 I am guessing you are trying to do something like: 我猜您正在尝试执行以下操作:
<xsl:template match="/root">
<xsl:variable name="columns" select="SelectValue"/>
<tr>
<td>
<xsl:value-of select="SubRoot/*[local-name()=$columns]"/>
</td>
</tr>
</xsl:template>
which given your input example will return: 给定您的输入示例将返回:
<tr>
<td>One</td>
</tr>
Within xsl:for-each select="SubRoot", the SubRoot is the context node, so you should not be selecting down to a further SubRoot. 在xsl:for-each select =“ SubRoot”中,SubRoot是上下文节点,因此您不应选择其他SubRoot。 So you want
所以你要
<xsl:for-each select="SubRoot">
<tr>
<td>
<xsl:value-of select="@*[local-name()=$columns]"/>
</td>
</tr>
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