强制结束使用计时器接受输入的函数

Question

I've tried using the the solution posted here:

How would I stop a while loop after n amount of time?

but that loop doesn't end with the function im running that accepts inputs. How do I force function5 to exit?

    while True:
                test = 0
                if test == 5 or time.time() > timeout:
                    print "time's out!"
                    break
                test = test - 1
                function5()
   def function5():
                receiver = raw_input("enter something: ")

Answer 1

You've already identified your problem. This won't work because when you call raw_input() the program will wait forever until the user types something, and what you want is for the timeout to somehow interrupt raw_input().

Here is a *nix-only solution:

Keyboard input with timeout in Python