PowerShell：从压缩存档中提取特定文件/文件夹

Question

Say foo.zip contains:

a
b
c
|- c1.exe 
|- c2.dll 
|- c3.dll

where a, b, c are folders.

If I

Expand-Archive .\foo.zip -DestinationPath foo 

all files/folders in foo.zip are extracted.
I would like to extract only the c folder.

Answer 1

try this

Add-Type -Assembly System.IO.Compression.FileSystem

#extract list entries for dir myzipdir/c/ into myzipdir.zip
$zip = [IO.Compression.ZipFile]::OpenRead("c:\temp\myzipdir.zip")
$entries=$zip.Entries | where {$_.FullName -like 'myzipdir/c/*' -and $_.FullName -ne 'myzipdir/c/'} 

#create dir for result of extraction
New-Item -ItemType Directory -Path "c:\temp\c" -Force

#extraction
$entries | foreach {[IO.Compression.ZipFileExtensions]::ExtractToFile( $_, "c:\temp\c\" + $_.Name) }

#free object
$zip.Dispose()

Answer 2

This one does not use external libraries:

$shell= New-Object -Com Shell.Application 
$shell.NameSpace("$(resolve-path foo.zip)").Items() | where Name -eq "c" | ? {
    $shell.NameSpace("$PWD").copyhere($_) } 

Perhaps it can be simplified a bit.

Answer 3

Here is something that works for me. Of Course, you will need to edit the code to fit your objective

$results =@()

foreach ($p in $Path)
{


$shell = new-object -Comobject shell.application
$fileName = $p
$zip = $shell.namespace("$filename")

$Results +=  $zip.items()| where-object { $_.Name -like "*C*" -or  $_.Name -like 
"*b*"  }
}
foreach($item in $Results )
{

$shell.namespace($dest).copyhere($item)
}