[英]Tcl variable substitution inside $::
If I define the following list: 如果我定义以下列表:
set ::listofvariablesn [list {"inputfile" "Input file"}]
set ::inputfile "Somefile or numbers"
I can check if the variable ::inputfile exists using: 我可以使用以下命令检查变量:: inputfile是否存在:
foreach a $::listofvariablesn {
if {[info exists ::[lindex $a 0]]} {
puts "Ok"
}
}
But I cannot access the value of ::inputfile using: 但是我无法使用以下方式访问:: inputfile的值:
foreach a $::listofvariablesn {
if {[checkvl "Input file" $::[lindex $a 0] 1 0 0 0]} {
puts "Ok"
}
}
I got the error: can't read "::": no such variable 我收到错误:无法读取“ ::”:没有这样的变量
Is there a way to get this substitution done? 有没有办法完成这种替换? I mean turn $::[lindex $a 0] into $::inputfile so I can access the value of ::inputfile
我的意思是将$ :: [lindex $ a 0]转换为$ :: inputfile,以便我可以访问:: inputfile的值
Thanks a lot 非常感谢
The $
is a shortcut, and can't do double substitution. $
是快捷方式,不能进行双替换。 Use the set
command: 使用
set
命令:
if {[checkvl "Input file" [set ::[lindex $a 0]] 1 0 0 0]} {
Apart from the longhand form of $
, the one-argument form of the set
command, there is also the option to create an alias of the variable (with a known name) using upvar 0
. 除了
$
的单字形式( set
命令的单参数形式)之外,还可以使用upvar 0
创建变量(具有已知名称)的upvar 0
。 For example: 例如:
upvar 0 $a b
puts "exists: [info exists b]"
puts "value: $b"
Anything you do to the variable b
(except changing the upvar
) will be performed on the variable that was named by $a
. 您对变量
b
所做的任何操作(更改upvar
除外)都将在$a
命名的变量上执行。
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