无法使用Java在Selenium Webdriver中的弹出窗口中单击按钮

Question

I am trying to click on a Yes button on a pop-up window in Selenium and not able to do so. HTML code is :

<div id="dialoguebuttons">    
    <div style="left: 60px; color: rgb(0, 102, 153); padding-top: 5px; font-size: 16px; font-weight: bold; float: left; position: relative;" id="dialog_question">Activate Riskfirst Rapid?</div>
        <a id="dialogYesButton" class="button btn-orng" tabIndex="101" href="#">
            <span class="btn-inner">Yes</span>
        </a>
        <a id="dialogNoButton" class="button btn-orng" tabIndex="102" href="#">
            <span class="btn-inner">No</span>
        </a>
    </div>
</div>

Java code I am trying to execute:

driver.findElement(By.xpath(//*[@id="save_quote_button"]/span)).click(); // After this the pop-up window gets displayed
driver.findElement(By.xpath(//*[@id="dialogYesButton"]/span)).click(); // Trying to click on the Yes button on the pop-up

It just skips the step without actually giving any error.

Answer 1

As you are trying to click on the Yes button, this xpath may help you:

driver.findElement(By.xpath(//*[@id="dialoguebuttons"]/a[text()='Yes')).click();

Let me know if this helps you.

Answer 2

If you are using firefox browser then install firebug Addon and firepath Addon and inspect that element using firepath and paste here that xpath between double quotes mentioned in below code:

driver.findElement(By.xpath(" ")).click();

If you are not familiar with firebug refer this link and try it. It will help you out.