Javascript REGEX：忽略两者之间的任何内容？

Question

How do I ignore anything in between with Javascript RegEx?

For example, I want to detect all three words: how are you in that order.

My regex:

var pattern = /([how]+[are]+[you]+)/i;

pattern.test("howare"); //false <--- expected (correct)
pattern.test("areyou"); //false <--- expected (correct)
pattern.test("howareyou"); //true <--- expected (correct)
pattern.test(" howareyou! "); //true <--- expected (correct)
pattern.test("how are  you"); //false <--- this should match!
pattern.test("how areyou  "); //false <--- this should match!

But then I want to ignore anything in between them.

Answer 1

You just want to add a wildcard in between your words by using

.* // 0 or more of any character

Regex rules are by default greedy, so trying to match are will take precedence over .* .

To note however you need to take out your square brackets as they'll currently allow things to match that shouldn't. For example they would allow hooooowareyou to match, as the square brackets allow all of the given characters, and the + indicates 1 or more.

Try something like:

how.*are.*you

It's unclear if you want all your test cases to pass, if you do then here's an example of this answer in action https://regex101.com/r/aTTU5b/2

Answer 2

You can use this regex:

how.*?are.*?you

This will ensure that how , are and you are present in the same order and ignore any characters in-between. So it will return a match for howwww areee!#%@!$%$#% you? etc. Check out more positive and negative cases using the demo link below:

Demo: https://regex101.com/r/rzhkHC/3