如何按行拆分文件中的数字，并将行分配到新列表中？

Question

How to split numbers in a file by lines, and assign the lines into new lists?

For example,
(numbers below are in a file)

2 56 39 4 
20 59 30 68 4
28 50 7 68 95 05 68

I want to make it

List1=[2, 56, 39, 4]
List2=[20, 59, 30, 68, 4]
List3=[28, 50, 7, 68, 95, 05, 68 ]

Answer 1

This is untested, but you would do something similar to the following.

list = []
with open(filename, 'r') as f:
    for line in f:
        list.append(line.split(" ")) # Split the space-delimited line into a list and add the list to our master list

Remember that list is now a list of lists of string elements representing the numbers on each line. You'll have to do type conversion when accessing these elements to get an actual number (use something like int(list[list_index][number_index]) ).

Answer 2

try:

result = []
with open(filename) as f:
    for line in f:
        result.append(map(int, line.strip().split()))

print(result)

Output:
[[2, 56, 39, 4], [20, 59, 30, 68, 4], [28, 50, 7, 68, 95, 5, 68]]

Answer 3

You didn't mention if you cared that the output will remains a string, so this is the easiest IMO:

with open('filename') as file:
    lines = [row.split() for row in f.read()]

Answer 4

This is tested:

 with open('source.txt') as source:
     lines = [line.split() for line in source.readlines()]

Output:
[['2', '56', '39', '4'], ['20', '59', '30', '68', '4'], ['28', '50', '7', '68', '95', '05', '68']]