[英]Dynamically create a generic type which use the type itself as generic parameter
Here a dummy code to explain my problem: 这里有一个虚拟代码来解释我的问题:
public class A<TX, TA> where TA : A<TX, TA>
{
}
public void Do()
{
var doy = typeof(A<,>).MakeGenericType(typeof(string), null/*??????*/));
}
How can I make a type from my generic type, if I can't identifty my type to use it as parameter? 如果我无法识别我的类型以将其用作参数,如何从我的泛型类型中创建类型?
Thanks for your help. 谢谢你的帮助。
Edit, example of doing it statically: 编辑,静态执行的示例:
public abstract class A<TX, TA> where TA : A<TX, TA>
{
public TA ChainMethod()
{
return (TA)this;
}
}
public class AConcrete : A<string, AConcrete>
{
public AConcrete OtherMethod()
{
return this;
}
}
public class App
{
public static void Start()
{
new AConcrete().ChainMethod().ChainMethod().OtherMethod();
}
}
You need to design your class hierarchy. 您需要设计类层次结构。 It seems like it's not quite there yet.
好像还没到那里。 Please check out this example, hope it will give you an idea:
请看看这个例子,希望它会给你一个想法:
abstract class BaseBuilder<TBrick>
{
public BaseBuilder<TBrick> AddBrick(TBrick brick)
{
// ...
return this;
}
}
class Builder : BaseBuilder<ConcreteBrick>
{
public Builder AddRoof()
{
// ...
return this;
}
public new Builder AddBrick(ConcreteBrick brick)
{
base.AddBrick(brick);
return this;
}
}
And it will look like this: 它看起来像这样:
new Builder()
.AddBrick(new ConcreteBrick())
.AddBrick(new ConcreteBrick())
.AddRoof();
I think you won't be able to chain calls with inheritance if you don't override methods with new
keyword like I suggested. 如果你不像我建议的那样使用
new
关键字覆盖方法,我认为你将无法使用继承链接调用。 Though you can implement things easily if you give up an idea of chaining calls. 虽然如果你放弃链接呼叫的想法,你可以轻松实现。
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