Javascript：事件未调用已提交的bind（..）-回调的副本：-/

Question

bind() should return a copy of the original function.. Yet when passing this copy as a callback, the original function is called :-( Tested with Chrome, Firefox and Edge. So where is my error in reasoning ? bind（）应该返回原始函数的副本。但是，当将此副本作为回调传递时，原始函数称为：-(经过Chrome，Firefox和Edge的测试。那么我的推理错误在哪里？

<html><body>
<script>    
// new api to wrap these nested Cordova callbacks ..
ScanDir = function (sPath, rCallback, iStep){
  yes = _Yes.bind(rCallback);   // should return a copy/newInstance of _Yes !?!
  yes.iStep = iStep;

  // simulate a cordova callback ..
  document.getElementById("test").addEventListener("click", yes);
}

_Yes = function YES(o){
    // this is not the new instance returned by bind(..):
    alert(_Yes.iStep);  // = undefined
    alert(YES.iStep);   // = undefined
    alert(arguments.callee.iStep);  // = undefined

    alert(yes.iStep); // wrong, 'yes' must not be global...
}
</script>
<span id="test">click here to trigger callback</span>
<script>
    // code that uses my new api..
    function Go(v){
        if (!v.iStep)   return ScanDir(v,Go,1);
        alert("continue with switch("+v.iStep+")");
    }

    Go("Music/");
</script>
</body></html>

debug the code here: http://www.robosoft.de/forums/bug.htm 在此处调试代码： http : //www.robosoft.de/forums/bug.htm

Answer 1

The best solution would be: 最好的解决方案是：

yes = _Yes.bind({callback:rCallback,iStep:iStep});

Inside _Yes you can access: 在_是内，您可以访问：

this.callback();
alert(this.iStep);

And no, bind does not create a new function, it binds the function... 不，bind不会创建新功能，它会绑定功能...

Javascript：事件未调用已提交的bind（..）-回调的副本：-/

问题描述

1 个解决方案

解决方案1
1 已采纳 2017-05-07 09:32:24

Javascript：事件未调用已提交的bind（..）-回调的副本：-/

问题描述

1 个解决方案

解决方案1 1 已采纳 2017-05-07 09:32:24

解决方案1
1 已采纳 2017-05-07 09:32:24