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使用内部联接3个表不显示结果

[英]Not Displaying Results with Inner Join 3 Tables

I am trying to inner join 3 tables that is from OS TICKET Database. 我正在尝试内部联接来自OS TICKET数据库的3个表。

The code I am using is $qry = "SELECT qbcd_user_email.address, qbcd_user_email.user_id FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.$email.') ORDER BY qbcd_ticket.ticket_id DESC"; 我使用的代码是$qry = "SELECT qbcd_user_email.address, qbcd_user_email.user_id FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.$email.') ORDER BY qbcd_ticket.ticket_id DESC";

Code is returning: 代码正在返回:

string(287) "SELECT qbcd_user_email.address, qbcd_user_email.user_id FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.patrick.kershner@gmail.com.') ORDER BY qbcd_ticket.ticket_id DESC"

but it is not displaying anything in the while clause: 但在while子句中未显示任何内容:

while ($row = mysqli_fetch_assoc($result)){
echo $row['qbcd_ticket.number]."<br>";} 

I am not sure what is going on, or why its not displaying the results. 我不确定发生了什么,或者为什么它不显示结果。

Can someone check out my code above and verify? 有人可以检出我上面的代码并进行验证吗?

尝试将数字添加到您选择的属性中

$qry = "SELECT qbcd_user_email.address, qbcd_user_email.user_id, qbcd_ticket.number FROM qbcd_user_email INNER JOIN qbcd_user ON qbcd_user.id = qbcd_user_email.user_id INNER JOIN  qbcd_ticket ON qbcd_ticket.user_id WHERE (qbcd_user_email.address = '.$email.') ORDER BY qbcd_ticket.ticket_id DESC"

the first table is: 第一个表是:

qbcd_ticket:
rows:

ticket_id | number | user_id | user_email_id | status_id | dept_id | and more...
5     |  762086|   2     |      0    |      1|  1  |    


the next is qbcd_user_email
rows:
id | user_id | flags | address
2  |    2    |  0    |  example@demo.com

the last is: qbcd_user
id | org_id | default_email_id | status | name              | created             | updated 
2  |    0   |   2          |     0  |  Patrick Kershner | 2017-03-03 10:44:28 | 2017-03-03 10:44:28

The information that I need to display, is all corresponding Tickets associated with the customer where it = the email address. 我需要显示的信息是与客户相关联的所有对应的票证,其中=电子邮件地址。

the only static variable that will not change is $_SESSION['user_email']; 唯一不变的静态变量是$_SESSION['user_email']; which is logged by logging into the members area. 通过登录成员区域进行记录。

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