[英]C++ template method to specialize union types
Suppose I have a union: 假设我有一个工会:
union U{
int i;
float f;
};
I want to write a generic method that uses it as a float or int. 我想编写一个将其用作float或int的通用方法。 Something like this:
像这样:
template <typename T>
T sum(std::vector<U> vec){
T res(0);
for (U &v: vec){
res += ... // use v.i or v.f depending on what T is
}
return res;
}
Is there a way to do this? 有没有办法做到这一点? This was just an example method.
这只是一个示例方法。 I have a much longer, complicated method, and I don't want to duplicate it just to switch which union type it is using.
我有一个更长,更复杂的方法,我不想复制它只是为了切换它使用的是哪种联合类型。
Specialization would work: 专业化将起作用:
template <typename T> T const & get(U const &);
template <> int const & get<int>(U const & u) { return u.i; }
template <> float const & get<float>(U const & u) { return u.f; }
Usage: 用法:
for (U & v : vec) { res += get<T>(v); }
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