[英]bash extract xml attribute value using xmllint
I am extracting an attribute value from xml file, but I get an error. 我正在从xml文件提取属性值,但出现错误。 I'd like to extract the value for key="qua"
in the firstpart element. 我想在第一部分元素中提取key="qua"
的值 。 Here is my script, but below you find the errors: 这是我的脚本,但是在下面您会发现错误:
#!/bin/bash
myfile=$1
myvar=$(echo 'cat //firstpart/step/category/id/info[@key="qua"]/@value' | xmllint --xpath "$myfile" | awk -F'[="]' '!/>/{print $(NF-1)}')
echo "$myvar"
how my xml file looks like: 我的xml文件看起来如何:
<?xml version='1.0' encoding='UTF-8'?>
<firstpart>
<step name="Home">
<category name="one">
<id name="tools">
<info key="qua" value="1"/>
</id>
</category>
</step>
<step name="Contact">
<category name="two">
<id name="tools">
<info key="qua" value="2"/>
</id>
</category>
</step>
...
</firstpart>
<secondpart>
<step name="office">
<category name="one">
<id name="tools">
<info key="qua" value="100"/>
</id>
</category>
</step>
<step name="Contact">
<category name="two">
<id name="tools">
<info key="qua" value="200"/>
</id>
</category>
</step>
...
</secondpart>
the errors I get: 我得到的错误:
awk: run time error: negative field index $-1
FILENAME="-" FNR=71 NR=71
./mybash.sh: line 3: $: command not found
./mybash.sh: line 4: $: command not found
It looks like you call xmllint
in wrong way. 看来您以错误的方式调用xmllint
。
xmllint --xpath '//firstpart/step/category/id/info[@key="qua"]/@value' FILE.xml
Result: 结果:
value="1" value="2"
Complete script: 完整的脚本:
#!/bin/bash
str=$(xmllint --xpath '//firstpart/step/category/id/info[@key="qua"]/@value' $1)
entries=($(echo ${str}))
for entry in "${entries[@]}"; do
result=$(echo $entry | awk -F'[="]' '!/>/{print $(NF-1)}')
echo "result: $result"
done
May be, it's not better solution, but at least it works :) 可能是,这不是更好的解决方案,但至少它可以工作:)
Get value of attribute with xmllint: 使用xmllint获取属性的值:
xmllint --xpath 'string(//firstpart/step[1]/category/id/info/@value)' file.xml
Output: 输出:
1
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.