我们需要 BiFunction 接口做什么？

Question

The definition of the BiFunction interface contains a method apply(T t, U u) , which accepts two arguments. However, I don't understand the use or purpose of this interface and method. What do we need this interface for?

Answer 1

The problem with this question is that it's not clear whether you see the purpose of a Function , which has a method apply(T t) .

The value of all the functional types is that you can pass code around like data. One common use of this is the callback , and until Java 8, we used to have to do this with anonymous class declarations:

ui.onClick(new ClickHandler() {
    public void handleAction(Action action) {
        // do something in response to a click, using `action`.
    }
}

Now with lambdas we can do that much more tersely:

ui.onClick( action -> { /* do something with action */ });

We can also assign them to variables:

Consumer clickHandler = action -> { /* do something with action */ };
ui.onClick(clickHandler);

... and do the usual things we do with objects, like put them in collections:

Map<String,Consumer> handlers = new HashMap<>();
handlers.put("click", handleAction);

A BiFunction is just this with two input parameters. Let's use what we've seen so far to do something useful with BiFunctions :

Map<String,BiFunction<Integer,Integer,Integer>> operators = new HashMap<>();
operators.put("+", (a,b) -> a + b);
operators.put("-", (a,b) -> a - b);
operators.put("*", (a,b) -> a * b);

...

// get a, b, op from ui
ui.output(operators.get(operator).apply(a,b));

Answer 2

One of usages of BiFunction is in the Map.merge method.

Here is an example usage of the Map.merge method, which uses a BiFunction as a parameter. What merge does is basically replaces the value of the given key with the given value if the value is null or the key does not have a value. Otherwise, replace the value of the given key after applying the BiFunction .

HashMap<String, String> map = new HashMap<>();
map.put("1", null);
map.put("2", "Hello");
map.merge("1", "Hi", String::concat);
map.merge("2", "Hi", String::concat);
System.out.println(map.get("1")); // Hi
System.out.println(map.get("2")); // HelloHi

If a BiFunction were not used, you would have to write a lot more code, even spanning several lines.

Here is a link that shows all the usages of BiFunction in the JDK: https://docs.oracle.com/javase/8/docs/api/java/util/function/class-use/BiFunction.html

Go check it out!

Answer 3

An extra example of BiFunction is reduce() :

public static void main(String[] args) {

        List<Integer> list = new ArrayList<>(Arrays.asList(5,5,10));

        Integer reduce = list.stream().reduce(0, (v1,v2) -> v1+v2);
        System.out.println(reduce); // result is: 20

}