[英]How to fetch the results from two tables based on mobile
Here i have two tables, i want get the results from this two tables.i tried lot but i am unable to get the exact results can you please any help me, i am using this application in codeiniter. 在这里我有两个表,我想从这两个表中获取结果。我尝试了很多,但我无法获得确切的结果,请您帮帮我,我正在codeiniter中使用此应用程序。
First Table 第一张桌子
new_staff
新员工
staff_id firstName Mobile userType
1 Soupranjali 9986125566 Teacher
2 Sujata 8553880306 Teacher
Second Table 第二表
new_student
新生
student_id first_Name fatherMobile user_type
1 janarthan 8553880306 Student
2 Santanu 8277904354 Student
3 Sarvan 8553880306 Student
here 8553880306 both table this mobile number is present, so want get to the both table results 这里8553880306这两个表都存在此手机号,因此要获取两个表的结果
Expected Results
预期成绩
{
"status": "Success",
"Profile": [
{
"staff_id": "2",
"firstName": "Sujata",
"userType" : "Teacher"
},
{
"student_id": "1",
"firstName": "janarthan",
"user_type" : "Student"
},
{
"student_id": "3",
"firstName": "Sarvan",
"user_type" : "Student"
}
]
}
So tried like this but i unable to get the answer, so please anyone help me, 如此尝试过,但我无法获得答案,所以请任何人帮助我,
my model
我的模特
public function android_memberList($mobile)
{
$this->db->select('new_staff.staff_id, new_staff.firstName, new_staff.userType');
$this->db->from('new_staff');
$this->db->join('new_student', 'new_student.fatherMobile = new_staff.Mobile');
$query1 = $this->db->get();
# result_array is used to convert the data into an array
$result_new_staff = $query1->result_array();
$this->db->select('new_student.student_id, new_student.first_Name, new_student.user_type');
$this->db->from('new_staff');
$this->db->join('new_student', 'new_student.fatherMobile = new_staff.Mobile');
$query2 = $this->db->get();
# result_array is used to convert the data into an array
$result_new_student = $query2->result_array();
$final_result=array_merge($result_new_staff,$result_new_student);
$result["status"] = "Success";
$result["Profile"] = $final_result;
echo json_encode($result);
}
Based on my query it is returning the output like this, but this is not my expected json fomat 根据我的查询,它将返回这样的输出,但这不是我期望的json fomat
my result
我的结果
{
"status": "Success",
"Profile": [
{
"staff_id": "2",
"firstName": "Sujata",
"userType": "Teacher"
},
{
"staff_id": "2",
"firstName": "Sujata",
"userType": "Teacher"
},
{
"student_id": "1",
"first_Name": "janarthan",
"user_type": "Student"
},
{
"student_id": "2",
"first_Name": "Santanu",
"user_type": "Student"
}
]
}
Use Group by in select query
在选择查询中使用分组依据
public function android_memberList($mobile)
{
$this->db->select('new_staff.staff_id, new_staff.firstName, new_staff.userType');
$this->db->from('new_staff');
$this->db->join('new_student', 'new_student.fatherMobile = new_staff.Mobile');
$this->db->group_by('new_staff.staff_id');
$query1 = $this->db->get();
# result_array is used to convert the data into an array
$result_new_staff = $query1->result_array();
$this->db->select('new_student.student_id, new_student.first_Name, new_student.user_type');
$this->db->from('new_staff');
$this->db->join('new_student', 'new_student.fatherMobile = new_staff.Mobile');
$this->db->group_by('new_staff.staff_id');
$query2 = $this->db->get();
# result_array is used to convert the data into an array
$result_new_student = $query2->result_array();
$final_result=array_merge($result_new_staff,$result_new_student);
$result["status"] = "Success";
$result["Profile"] = $final_result;
echo json_encode($result);
}
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