具有动态路径的Apache Camel文件组件

Question

I am trying to set dynamic path in camel file component to avoid platform specific paths. But camel is not allowing this as it doesn't expect $ in directory path.

What I am trying to do is to set a VM param say file.home and then use this into my file component like

file:\\${file.home}\\type1

This will allow me to eliminate the platform specific path directly. I tried externalizing this into property file but then Spring doesn't understand the camel specific dynamic language for eg ${in.header.abc}

Can someone help me out in achieving this.

Answer 1

以下是有关在骆驼和/或spring xml中使用属性的一些详细信息： http : //camel.apache.org/using-propertyplaceholder.html

Answer 2

You can use dynamic uri but only in to endpoints (using specific components). You can't use it as from .

There you can find explanation how to use toD (from Camel 2.16) or recipientList : How to use dynamic URI in to

But as I said - there is only possibility to use it in to . It's not possible to use it in from . As a workaround, you have to write a route for each location you are expecting to be in use. You can also use autoCreate=false option to not creating other directories automatically, because for example Linux path without autoCreate=false option: /home/user/test will create directory structure in Windows c:\\home\\user\\test

Answer 3

Since Camel 2.16

We can use

.from("file://folder")
.toD("file://folder/${file:onlyname}")

Answer 4

Those answers are not correct. If you use a BridgePropertyPlaceholderConfigurer and a PropertiesComponent, you can use dynamic values everywhere.

<bean id="bridgePropertyPlaceholder" class="org.apache.camel.spring.spi.BridgePropertyPlaceholderConfigurer">
    <property name="properties">
        <value>
...normal property syntax name=value - use this in test definitions
        </value>
    </property>
</bean>

Or use something like this in real application

<bean id="dummyPropertyPlaceholder" class="org.apache.camel.spring.spi.BridgePropertyPlaceholderConfigurer">
    <property name="location" value="classpath:/dummy.properties" />
</bean>

eg

    <route id="DummyRoute">
        <from uri="file:{{dummy.int.dir}}?delay={{poll.delay}}&amp;initialDelay={{initial.delay}}&amp;{{readlockChanged}}&amp;move={{root}}/{{dummy.arch.dir}}/{{archive.dir}}&amp;moveFailed={{error.dir}}&amp;scheduledExecutorService=#scheduledExecutorService" />
            <to uri="file:{{root}}/{{dummy.int.destination.dir}}" />
    </route>

There is a trick with later versions of Camel: use $simple{file.path} instead of ${file.path} so Spring won't strip your ${} and pass the bare file.path to Camel. Eg a move on an input 'from' uri might be like this:

move=archive/$simple{date:now:yyyyMMdd}/$simple{file:name}

http://camel.apache.org/how-do-i-use-spring-property-placeholder-with-camel-xml.html

http://camel.apache.org/using-propertyplaceholder.html

Answer 5

According to Camel File Component :

Camel supports only endpoints configured with a starting directory. So the directoryName must be a directory. If you want to consume a single file only, you can use the fileName option eg, by setting fileName=thefilename. Also, the starting directory must not contain dynamic expressions with ${} placeholders. Again use the fileName option to specify the dynamic part of the filename .

So, you could do somethings like:

from(...).to("file://?fileName=${somePathAndSomeFile}").to(...)

Answer 6

Some of the comments/answers in this thread are misleading, as it's possible to set the value of "from" endpoint URI to have a value of a directory taken from a properties file as asked.

Place propertyPlaceholder element under camelContext, and ensure that the properties file could be found in the classpath

<propertyPlaceholder location="dir.properties" />
<from id="_fromInputFolder" uri="file:{{fromDir}}?"/>