[英]Code Sniffer error into js code
I have been searching since yesterday for the resolution of two code sniffer errors : 从昨天开始,我一直在寻找两个代码嗅探器错误的解决方案:
62 | ERROR | [x] Expected 1 space after closing parenthesis; found
| | " options.keys = $.extend(\n
Here is my code : 这是我的代码:
if (newOptions.keys) options.keys = $.extend(
{
shift: 1,
ctrl: 'resize' },
newOptions.keys
);
I would like to have the eye of an outside person to solve this, thanks for your attention :) 我想请外部人解决此问题,谢谢您的关注:)
I'd have to see the rest of the file to be able to generate and fix that Expected 1 space after closing parenthesis
error, but if you want to format that IF statement in a way that PSR2 is happy with, you'd do this: 我必须查看文件的其余部分,才能
Expected 1 space after closing parenthesis
错误Expected 1 space after closing parenthesis
生成并修复“ Expected 1 space after closing parenthesis
,但是如果要以PSR2满意的方式格式化IF语句,则可以执行此操作:
if (newOptions.keys) {
options.keys = $.extend(
{
shift: 1,
ctrl: 'resize'
},
newOptions.keys
);
}
If you are using a standard that allows inline control structures, you can ignore the PSR2 error for that and use this code instead: 如果使用允许内联控制结构的标准,则可以为此忽略PSR2错误,而使用以下代码:
if (newOptions.keys) options.keys = $.extend(
{
shift: 1,
ctrl: 'resize'
},
newOptions.keys
);
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