如何在另一个页面的php类中使用定义的变量值

Question

I'm fairly new using PHP classes, I have done some PHP using the procedural method for a while but never fully done proper object oriented programming on php. Which brings me to my question:

I have one file called classes.php where I intend to define all my php classes. Inside that file I have created a class as follows:

require_once("connection.php");

class User
    {

        public function getUserInfo() {
            $userinfo = mysqli_query($con,"SELECT * FROM users WHERE username='". $_SESSION['username'] ."'");
            while($row = mysqli_fetch_assoc($userinfo)) {

                // USER DETAILS:
                $userid = $row['id'];
                $username = $row['username'];
                $userfirstname = $row['first_name'];
                $userlastname = $row['last_name'];
                $useremail = $row['email'];
                $useraddress1 = $row['address_line_1'];
                $useraddress2 = $row['address_line_2'];
                $userpostcode = $row['postcode'];
                $userphone = $row['phone'];
                $usermobile = $row['mobile'];
                $usercreated = $row['created'];
                $usermodified = $row['modified'];
                $useraccess = $row['access_level'];

            }
        }

    } // end of User

Now I want to use the values of the variables defined in that class in another page. But how can I access those values?

So far I'm trying this (unsuccessfully):

<?php
include "php_includes/classes.php";
$user = new User();
?>

<div class="somediv">
    <?php echo $user->getUserInfo($username) ?>
</div>

I have also tried:

<?php
    include "php_includes/classes.php";
    $user = new User();
    ?>

    <div class="somediv">
        <?php echo $user->$username ?>
    </div>

Is there any way to echo those variables in another page so I can use the user information in, for example, profile pages?

Thanks in advance.

Answer 1

Before your function you need make PUBLIC VARIABLE like:

public $userid; 

Then next in code in function you need to use:

$this->userid = $row['id'];

EDIT

Your calss need to be:

class User
    {

        public $userid;
        public function getUserInfo() {
            $userinfo = mysqli_query($con,"SELECT * FROM users WHERE username='". $_SESSION['username'] ."'");
            while($row = mysqli_fetch_assoc($userinfo)) {

                // USER DETAILS:
                $this->$userid = $row['id'];


            }
        }

    } // end of User

And you also need include this class file in other php page when you want show data.

Answer 2

you have to declare the variable as PUBLIC

class User
{
       public function getUserInfo() {
       $userinfo = mysqli_query($con,"SELECT * FROM users WHERE username='". $_SESSION['username'] ."'");
       while($row = mysqli_fetch_assoc($userinfo)) {

                        // USER DETAILS:
                        public $userid = $row['id'];

        }
        }
} 

For more information check here

Answer 3

you should return the value from function.

require_once("connection.php");

class User
    {

        public function getUserInfo() {
            $userinfo = mysqli_query($con,"SELECT * FROM users WHERE username='". $_SESSION['username'] ."'");
            $row = mysqli_fetch_assoc($userinfo);

            return row
        }

    } 

and now only have to show the detail of user

<?php
  include "php_includes/classes.php";
  $user = new User();
 ?>
 <div class="somediv">
    <?php $user_detail=$user->getUserInfo(); ?>
    <label>name:</label><br>
    <?php echo $user_detail["first_name"]; ?>
 </div>

Hence you can check whether row is null or not and whole array can be returned by this function of class any where this class included in file.