[英]Doubly-linked list insert method implementation - what node is being search for
I'm reviewing data structures and using this book . 我正在审查数据结构并使用这本书 。 When inserting a node, the list has to be traversed.
插入节点时,必须遍历列表。 But in the implementation of insert operation of a doubly-linked list DS I don't understand how can
k
be equal to position
: 但是在实现双向链表DS的插入操作时,我不了解
k
如何等于position
:
while ((k < position - 1) && temp->next!=NULL) {
temp = temp->next;
k++;
}
if (k!=position) { <----------------- this will true all the time?!
printf("Desired position does not exist\n");
}
What am I missing? 我想念什么? Or is this a typo?
还是这是错字?
Thanks in advance! 提前致谢!
Here is the full method implementation: 这是完整的方法实现:
void DLLInsert(struct DLLNode **head, int data, int position) {
int k = 1;
struct DLLNode *temp, *newNode;
newNode = (struct DLLNode *) malloc(sizeof( struct DLLNode ));
if (!newNode) {
printf("Memory Error");
return;
}
newNode->data = data;
if (position == 1) {
newNode->next = *head;
newNode->prev = NULL;
if (*head) {
(*head)->prev = newNode;
}
*head = newNode;
return;
}
temp = *head;
while ((k < position - 1) && temp->next!=NULL) {
temp = temp->next;
k++;
}
if (k!=position) {
printf("Desired position does not exist\n");
}
newNode->next=temp->next;
newNode->prev=temp;
if (temp->next) {
temp->newNode->prev=newNode;
}
temp->next=newNode;
return;
}
I think you don't miss something - k!=position
will always be true at this point in the code; 我认为您不会错过任何内容
k!=position
在此刻将始终为真; the only chance that k!=position
would be true
is when position==1
, but in this case the function returns before reaching the if
. k!=position
为true
的唯一机会是在position==1
,但是在这种情况下,函数在到达if
之前返回。 The check should rather be if(temp==NULL)
. 检查应该是
if(temp==NULL)
。
There are some other issues, which let me think that the author did not test (actually not even compile) the code: 还有其他一些问题,让我认为作者没有测试(实际上甚至没有编译过)代码:
temp->newNode->prev=newNode; // will this compile? I don't think that there's a member named `newNode`.
The code will crash if *head
points to NULL
, but one passes a position > 1
; 如果
*head
指向NULL
,但代码传递的position > 1
,则代码将崩溃。
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