Python套接字编程recv

Question

I've started with python today and i'm looking into socket programming atm. Ive connected to an ip and port with a socket instance and im trying to read the next 1024 bytes on the socket with the recv method. When im trying to store it in a variable, I get an error telling me that the socket times out, tried increasing it but didn't help.

Code:

>>> import socket
>>> socket.setdefaulttimeout(2)
>>> s = socket.socket()
>>> s.connect(("192.168.95.148",21))

error:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
socket.timeout: timed out

Answer 1

You set a timeout in socket.setdefaulttimeout(2) , therefore it raises an exception.

Try this instead:

import socket
s = socket.socket()
socket.setdefaulttimeout(10) #set timeout for ten seconds (can be whatever you want)
try:
    s.connect(("192.168.95.148",21))
except Exception as e:
    print("An error occured:\n{}".format(e))