读取文件并逐行打印python

Question

I have a file with different planets written on each line. I'm trying to iterate through it using the with function and print so the the output looks like this:

1 - mercury
2 - venus 
etc...

but my output currently looks like this:

(1, '-', <open file 'planets.txt', mode 'r' at 0x7f87dea69660>)
(2, '-', <open file 'planets.txt', mode 'r' at 0x7f87dea69660>)
(3, '-', <open file 'planets.txt', mode 'r' at 0x7f87dea69660>)
(4, '-', <open file 'planets.txt', mode 'r' at 0x7f87dea69660>)

my code is this:

with open("planets.txt") as p:
    i=0
    for line in p:
        i += 1
        print(i, '-', p)

How am I using with wrong or is it something else?

Answer 1

Instead of printing the line you print p - the file itself:

    print(i, '-', p)

Also, instead of making a new variable to count lines, you may use enumerate feature:

with open("planets.txt") as p:
    for i, line in enumerate(p, 1):
        print(i, '-', line)

UPD: You should also consider the fact, that the line you are getting from the file ends with a newline character and when you print(line) it adds another newline after it by defaulf. So your output will look like that:

1 - mercury

2 - venus 

etc...

to get

1 - mercury
2 - venus 
etc...

you need to specify end='' argument to print function. This way:

        print(i, '-', line, end='')

Answer 2

You want to print line not p :

with open("planets.txt") as p:
    i=0
    for line in p:
        i += 1
        print(i, '-', line) #refers to each line in p rather than the file handler

Answer 3

您应该将print(i, '-', p)更改为print(i, '-', line)