从Django视图返回响应时发生TypeError

Question

I've been trying to create a view for the url pattern

Urls.py

url(r'^task/', include('app.urls')),

Urls.py inside app.urls

url(r'^(?P<task_id>[0-9]+)/$', views.task, name='task'),

Which can be accessed by /task/:task_id . My corresponding view for task is

 def task(request, task_id): obj = Task.objects.get(pk=task_id) return HttpRequest("You're looking at a %s Task." % obj.type) 

The corresponding model for Task is this.

 class Task(models.Model): image = models.ImageField(upload_to='tasks') description = models.CharField(max_length=500) language = models.CharField(max_length=7, default='en', choices=LANGUAGES) type = models.CharField(max_length=20, default='Transliteration', choices=TASK_TYPES) date = models.DateTimeField(auto_now_add=True) def __str__(self): return self.language + ' ' + self.description 

I am successfully able to debug the task_id and obj values which exist but my webpage returns the following error.

 TypeError at /task/1/ __init__() takes exactly 1 argument (2 given) 

How can such an error be fixed?

Answer 1

Return HttpResponse instead of HttpRequest

def task(request, task_id):
    obj = Task.objects.get(pk=task_id)
    return HttpResponse("You're looking at a %s Task." % obj.type)