如何通过检查长度并比较Java中的文本来从数组中删除String？

Question

How to remove String from an array by checking length and comparing text in Java?

Suppose user search for "Hi Tonki with Monkey"

String[] pattern = userSearchString.toLowerCase().split("\\s");

1) We want to remove "With" from pattern and

2) also want to remove pattern with less then 3 size like "Hi".

So pattern should contain Tonki and Monkey only.

It will be fuitful if anyone can suggest method from Apache Commons or Guava.

Using Java 1.6

Answer 1

A Java 8 solution would be to Stream the array and filter only the elements that you want, and collect it back into an array:

Arrays.stream(pattern)
      .filter(word -> !word.equals("with"))
      .filter(word -> word.length() >= 3)
      .toArray(String[]::new);

A pre-Java 8 solution would be to filter the array manually. However, we'll have to create a new array; but because we do not know the size of the new array in advance, we can use a List<String> and collect it to an array after adding its respective elements:

List<String> list = new ArrayList<>();

for (String word : pattern) {
    if (word.length() < 3 || word.equals("with")) {
        continue;
    }

    list.add(word);
}

list.toArray(new String[list.size()]);

There's no need to use external libraries if they aren't required!