[英]Python Exception Handling - exception raised with a string message, excepted as list of characters
I am trying to raise and except a custom exception with a message, but the message string prints as tuple of characters. 我试图提出一个消息的自定义异常,但消息字符串打印为字符元组。 My error class:
我的错误类:
class myError(Exception):
def __init__(self, arg):
self.args = arg
And try-raise-except part : 尝试加注 - 除了部分:
try:
raise myError('some message.')
except myError, e:
print e.args
This when raised properly, prints:` 当正确抬起时,打印:`
('s', 'o', 'm', 'e', ' ', 'm', 'e', 's', 's', 'a', 'g', 'e', '.', ' ')
Of course, I wanted 'some message. 当然,我想要一些消息。 '.
”。 What is going on?
到底是怎么回事?
You Don't need to declare __init__
in Your Exception: 您不需要在您的例外中声明
__init__
:
>>> class myError(Exception):
... pass
>>> raise myError('some message.')
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
__main__.myError: some message.
Your problem is that args
is already a member of Exception
, and it is defined as: 您的问题是
args
已经是Exception
的成员,它被定义为:
args
ARGS
The tuple of arguments given to the exception constructor赋予异常构造函数的参数元组
So you assign a tuple with an iterable (a string is an iterable of characters) and end with a tuple of characters. 所以你给一个带有iterable的元组(一个字符串是一个可迭代的字符),并以一个字符元组结束。
How to fix: 怎么修:
just use args
from Exception: 只使用Exception中的
args
:
class myError(Exception): pass try: raise myError('message') except myError as e: print(e.args[0])
use a new member name: 使用新成员名称:
class myError(Exception): def __init__(self, arg): self.msg = arg try: raise myError('message',) except myError as e: print(e.msg)
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