从一个条件为的表中检索数据，并在一个SELECT查询中检查另一个表中的记录

Question

Need in one query query retrieve data from one table with condition "where" simultaneously check if another table exists ip user, then display results in while display information whether there exists ip

tables:

Ips (
   Id int (10) not null auto_increment,
   User_id int (10) not null default '0',
   Ip varchar (40) not null
)

Users (
   Id int (11) not null auto_increment,
   Username varchar (35) not null,
   Email varchar (200) not null,
   Salt varchar (40) not null,
   Password varchar (40) not null,
   Country varchar (40) not null
)

What I want to get:

1. Get data from the users table with the condition "where country = 'paris' LIMIT 0.10"

2. Each time you check that the ips table exists with a user id and ip address with $ _SERVER ['REMOTE_ADDR']

3. If there is a record in the table ips display the information in while

My current problem code:

<?php

include "connect.php";

$db = mysqli_query($connect, "SELECT * FROM users JOIN ips ON ips.user_id=users.id ON ips.ip='".$_SERVER['REMOTE_ADDR']."' WHERE users.country='paris' LIMIT 0,10");

if (mysqli_num_rows($db)>0){
    while ($data = mysqli_fetch_assoc($db)){
        print_r($data);
        if (filter_var($data['ip'], FILTER_VALIDATE_IP)){ //check var is ip adress
            echo '<br>isset ip';
        }
    }
}else{
    echo 'not records';
}

?>

Ps: I could not find an answer in the proposals

Answer 1

试试这个查询：

SELECT * FROM Users WHERE Country ='paris' AND Id IN (SELECT User_id  FROM Ips  WHERE Ip = 'ip_adddress')