[英]Typescript Generator Property / Getter
Making a generator method in typescript is simple: 在typescript中创建一个生成器方法很简单:
class Foo {
*values() { yield 10 }
}
But I want to make a generator property , something like this: 但我想创建一个生成器属性 ,如下所示:
class Foo {
get *values() { yield 10 }
}
But that seems to be invalid. 但这似乎无效。 I can't seem to find any references to this question or workarounds (aside from the obvious of using Object.defineProperty explicitly, which would suck because it would be untyped).
我似乎无法找到任何对这个问题或变通方法的引用(除了显而易见的明显使用Object.defineProperty,这会很糟糕,因为它将是无类型的)。 Am I missing something?
我错过了什么吗? Is this supported?
这支持吗? If not, will it be?
如果没有,会是吗?
You could fake it with a backing method. 你可以用支持方法伪造它。
class Gen {
private *_values() {
yield 3;
yield 4;
}
public get values() {
return this._values();
}
}
let g = new Gen();
let v1 = g.values;
let v2 = g.values;
console.log(v1.next());
console.log(v1.next());
console.log(v1.next());
console.log(v2.next());
console.log(v2.next());
console.log(v2.next());
/* stdout
{ value: 3, done: false }
{ value: 4, done: false }
{ value: undefined, done: true }
{ value: 3, done: false }
{ value: 4, done: false }
{ value: undefined, done: true }
*/
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