简体   繁体   English

J查询错误:SyntaxError:丢失; 声明前

[英]J query Error: SyntaxError: missing ; before statement

I have some small issue in j query. 我在j查询中有一些小问题。 my code is like this 我的代码是这样的

var tt = 8*1;
var n = tt.toString();
var uu1 = n.split('*');

var count = uu1.length;

var table_id44 = '';

for(k = 0,m = 1; k < count-1; k++,m++)
{
var table_id44[m] = uu1[k];
}

when I put that i got error in console log SyntaxError: missing ; 当我在控制台日志中输入错误时出现SyntaxError:missing; before statement.please someone help. 在声明之前。请有人帮助。

table_id44 should be declared as an array. table_id44应该声明为数组。 and you don't need to redeclare the variable in the for loop. 并且您不需要在for循环中重新声明变量。

var tt = 8 * 1;
var n = tt.toString();
var uu1 = n.split('*');

var count = uu1.length;

var table_id44 = [];

for (k = 0, m = 1; k < count - 1; k++, m++) {
    table_id44[m] = uu1[k];
}

Try this, You are declaring it as string var table_id44 = ''; 试试看,您将其声明为字符串var table_id44 = ''; and using it as an array . 并将其用作array

var tt = "8 * 1";//use it as string so that you can further split it on *
var n = tt.toString();
var uu1 = n.split('*');

var table_id44 = [];

for (k = 0, m = 1; k < count - 1; k++, m++)
{
    table_id44[m] = uu1[k];//prevent multiple declaration in loop
}

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM