Ruby gsub检查或（||）模式

Question

Ruby Experts,

I'm trying to check and remove string from multiple files under a folder and below is my code snippet,

........
work_files = Dir.glob("E:\nano\*_access.txt")

val=File.open('E\new_dir\access_list.txt').read
val.each_line do |line|
    line.chomp!
    work_files.each do |file_name|
      text = File.read(file_name)
      new_content = text.gsub(( /#{Regexp.escape(line)}\,\s/, '')  || ( /#{Regexp.escape(line)}\n/, '' )) 
..........
........ 

from one of the files,like below I'm checking for the string ncr\\atxe5t (can occur multiple times also). its getting removed from the last line for the pattern (/#{Regexp.escape(line)}\\,\\s/, '') but its not getting removed from the last but one line for the pattern - /#{Regexp.escape(line)}\\n/, '' .

I;m getting the error like below

... ^ test.rb:14: syntax error, unexpected ',', expecting ')' ...| ( /#{Regexp.escape(line)}\\n/, '' ))

Eg. E:\\nano\\ids_access.txt

# Digital created on July 2016
# Digital Owner: John Cena (jxcgo)
# Digital access: create delete access

[pool]
@rem = ncr\abc_efg_dev, ncr\abc_efg_test, ncr\jx8go5, ncr\atxe5t
@digital_owner = ncr\atxe5t, ncr\yui30n, ncr\bhyrl4

I'm not sure whether or (||) condition pattern is allowed in gsub method but I want to make use of the gsub method only. is it possible in ruby. Thanks in advance. Hope I have explained clearly.

Answer 1

Nope, || is not usable in method args. I think that's what you want to do: gsub(/#{Regexp.escape(line)}\\,(\\s|\\Z)/, '') .